3x^2+20=x^2+2

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Solution for 3x^2+20=x^2+2 equation: 



3x^2+20=x^2+2

We move all terms to the left:

3x^2+20-(x^2+2)=0

We get rid of parentheses

3x^2-x^2-2+20=0

We add all the numbers together, and all the variables

2x^2+18=0

a = 2; b = 0; c = +18;
Δ = b2-4ac
Δ = 02-4·2·18
Δ = -144
Delta is less than zero, so there is no solution for the equation

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